What is the equation in slope-intercept form of the line that includes the point (36,0) and has a slope of 9/4?

y = 9/4x - 81

Step-by-step explanation:

Given the slope = 9/4

The point (36, 0) ; x1 = 36 ; y1 = 0

Slope intercept relation :

y = mx + c ; c = intercept, m = slope

Using the relation :

y - y1 = m(x - x1)

y - 0 = 9/4(x - 36)

y - 0 = 9/4x - 81

y = 9/4x - 81

Hence, the required equation is : y = 9/4x - 81

9/4 = slope ; - 81 = intercept

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

he kicked it up? is this the answer ?

step-by-step explanation: