In which set do all of the values make the inequality 3x-7_>11 true? {6,11,15} {0,7,12} {−2,3,6} {−5,0,5}

{6, 11, 15}

Step-by-step explanation:

Given the inequality expression 3x-7≥11

Add 7 to both sides

3x-7+7≥11+7

3x ≥ 18

Divide both sides by 3

3x/3 ≥ 18/3

x≥6

Hence the solution to the inequality are the values of x greater than or equal to 6. Hence the required solutions are {6, 11, 15}

table 1

step-by-step explanation:

1-16

2-32

4-64

8-128

all multiples of 16

beanburito

step-by-step explanation: