Hey every one I hope your having a good day and that every thing is going well but if your not busy can some one help me with my math hwk and sorry I have been asking for so much help also thank you so much :) ​

(a) 2 ≤ t < 4

(b) Yes, the data supports the statement

Step-by-step explanation:

(a) The median interval is given by the interval of the (n + 1)/2 th term

The number of customers that waited at the supermarket checkout, n = 80

Therefore, the median = (80 + 1)/2 th customer = 40.5 th customer = The41st customer

From the given table, the time interval of the 41 st customer = 2 ≤ t < 4

The class interval of the median = 2 ≤ t < 4

(b) The number of customers that wait less than 6 minutes is given as follows;

32 customers weight 0 ≤ t < 2 minutes

19 customers weight 2 ≤ t < 4 minutes

20 customers weight 4 ≤ t < 6 minutes

The total number of customers that wait less than 6 minutes = 32 + 19 + 20 = 71 customers

The percentage of customer that wait less than 6 minutes = 74/80 × 100 = 92.5% ≈ 90%

Therefore, the data supports the manager's statement that (approximately) 90% of the customers wait less than 6 minutes

(w – 2.5)(w + 2.5)

(–4v – 9)(–4v + 9)

step-by-step explanation: