“Write the equation of the line that passes through the points (0,7) and (-2,7). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.”

y = 7

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

Here, m = Slope of the line

b = y-intercept

Line passes through two points (0, 7) and (-2, 7)

Therefore, slope of the line will be,

m =

m =

m = 0

If the slope of a line is 0 then the graph of the line will be parallel to x-axis.

By substituting the value of slope in the equation,

Equation of the line will be,

y = 0(x) + b

y = b

Since, the given line passes through (0, 7),

Equation of the line will be,

y = 7

3201

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐