Caculate the temperature change if 3456 J of thermal energy was transferred into 3.0 kg of lead? The specific heat of lead is 128 J/kgo C.

9°C

Step-by-step explanation:

quantity of heat energy absorbed is expressed as;

Q = mcΔt

m is the mass

c is the specific heat capacity

Δt is the change in temperature

Substitute the given values

3456 = 3 * 128 Δt

3456 = 384Δt

Δt = 3456/384

Δt = 9°C

Hence the temperature change is 9°C

the correct answer to your question is a. 4^4

good luck my friend!

hope this !

maybe if i you could me by giving me brainliest?

! < 3

have a splendid day < 3 : )

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )