What is the area of the quadrilateral and what is the perimeter

Area of Trapezoid = (b1 + b2)h

                                         2

Area = (9 in + 17 in) (3 in = 1/4 ft)

                      2

A = (26 in)(3 in)/2

A = 78 in2/2

A = 39 in2

Perimeter = bi + b2 + 2l

             P = 9in + 17 in + 2(5 in)

             P = 26 in + 10 in

             P = 36 inches

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

what are you trying to solve here

step-by-step explanation: