If O is an angle in standard position and its terminal side passes through the point (1,-8), find the exact value of csc in simplest radical form.

From the given point (-1,3) we know

x = -1, y = 3 and the point in in quadrant II

r^2 = (-1)^2 + 3^2 = 10

r = √10

secθ = r/x = -√10/1 = -√10

You must memorize all 6 trig ratios in terms of x, y, and r

e.g. tanθ = y/x

etc

Step-by-step explanation:

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step-by-step explanation: