Use the quadratic formula (x - 6)2 + 3 to answer questions 15 - 20. 15. a =
a. 1
b. 4
1
c.
4
d. 6
16. k=
1
a.
4.
b. 6
c. 2
d. 3
17. The vertex of the parabola would be located at which coordinates?
a. (-6,3)
b. (6,3)
c. (3,-6)
d. (3,6)
18. The parabola would open
a. Upwards
b. Downwards
c. To the left
d. To the right
19. The axis of symmetry is located at x =
1
a.
4
b. 6
c. 2
d. 3
20. Because of the value of the leading coefficient, the parabola would have a
opening.
a. Narrow
b. Wide
c. Left
d. Right

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

step-by-step explanation:

what is the figure? attach a picture.

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.