Correct I’ll give brainlist no links or I’ll report

y = 5x -23

Step-by-step explanation:

Alright, for this, we need the slope and the y intercept. First, the slope.

So to find the slope, find any two points that the line goes over first. For example, the dotted point (5,2). Now for the other one, (4,-3) can be used.

Look for when the line is crossing over the points of the square graph, as this will help you with the next part.

For the next part, to find the slope, this is going to see how much the line has done up/down for how much we move forward or backwards on the line. With this, the equation:

y2-y1 / x2-x1 can be used, with the 2s and 1s being just to show that there are 2 separate points being used for it.

Next, plug it in with what's known:

2-(-3) / 5-4

5 / -1

Slope is 5.

Now, the y intercept needs to be found. To get this, we need the y value for where the line passes over where the x value is 0.

By knowing that the slope is 5, we can walk backwards to the y intercept to get this value. With this, for every number in x walked back, it will go down 5 y values:

5, 2 (Do -1, -5)

4, -3 (Do -1, -5)

3, -8 (Do -1,-5)

2, -13 (Do -1,-5)

1, -18 (Do -1,-5)

0, -23 (All done)

The y intercept is now found, along with the slope. Now these values can be both be plugged into the slope intercept equation, y=mx+b, where m is for the slope and b is where the y intercept goes.

y = 5x -23

step-by-step explanation:

51-50

step-by-step explanation: