Determine the approximate value of ø
a)41.89
b) 48.20
c)33.70
d)56.30

B,48.2

Step-by-step explanation:

To solve this we need to use SOH, CAH, TOA

we have the adjacent and hypotonouse so it's easiest to use CAH

let theta (angle) = x

cos(x)=4/6

to cancel the cos mulitply both sides by cos^-1 (2nd --> cos)

x=48.1896851

which rounds to 48.2

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.