What is the distance to the nearest tenth of a unit between point H ( -4,6 ) and point I ( 2,-3 )

10.81 units

Step-by-step explanation:

Given data

point H ( -4,6 ) and point I ( 2,-3 )

x1= -4

y1=6

x2= 2

y2=-3

The formula for the distance between two points is

d=√((x_2-x_1)²+(y_2-y_1)²)

d=√((2-(-4))²+(-3-6)²)

d= √(2+4)²+(-9)²)

d= √(6)²+(-9)²)

d= √36+81

d=√117

d= 10.81 units

Hence the distance between the points is 10.81 units

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.