Attendance to state pork throughout the year is found to be periodic and can be modeled by a function. The attendance ranges from a low of approximately 1,000,000 visitors in September to a high
of approximately 2,000,000 visitors in March. If t is the month number, where t = 1 is January, and
Nt) is the attendance in millions of visitors, which of the functions can be used to model this
behavior
N(t) = 2 sin(3+) - 1
N(t) = 15 sin (31)
+0.5
N) 05 sán(51) -15
Nt) = 0.5 m (2) 15
We

$6.42

step-by-step explanation:

it's a proportional graph.

step-by-step explanation:

8 x 5 = 40         (and you have -8x and -5y)

x= absiss

y= orderly

so you have a proportional graph.

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.

the first domain and range set to the left is matched with the top relation, and the second set the set in the middle goes with the bottom relation.