Select ALL the correct answers. Identify the two tables which represent quadratic relationships.

x 0 1 2 3
y -2 -4 -8 -16

x 0 1 2 3
y -4 -8 -10 -10

x 0 1 2 3
y 4 -4 -4 4

x 0 1 2 3
y -2 0 2 4

x 0 1 2 3
y 3 4 5 6

x 0 1 2 3
y 1 2 4 8

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.