100 pts and brainiest for the right answer A skateboard halfpipe is being designed for a competition. The halfpipe will be in the shape of a parabola and will be positioned above the ground such that its focus is 20 ft above the ground. Using the ground as the x-axis, where should the base of the halfpipe be positioned? Which equation best describes the equation of the halfpipe?

(0, 20); y equals one over eighty times x squared plus 20
(0, 20); y equals one over eighty times x squared minus 20
(0, 10); y equals one over forty times x squared plus 10
(0, 10); y equals one over forty times x squared minus 10

Option A , (0, 20); y equals one over eighty times x squared plus 20

Step-by-step explanation:

The equation of parabola is given by  

(X-h)^2 = 4p(Y-k)^2

In this case h = 0

So we get  

Y = X^2/4P +k

Focus point is (h, p+k) , p+k = 40

Hence h, k = (0,20)

P = 40-k = 20

Equation Y = X^2/80 +20

Hence, option A is correct

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: