A student has taken three math tests so far this semester. His scores for the first three tests were 71, 75, and 79. Part A: Suppose his test scores continue to improve at the same rate. What will be the grade on the sixth and (final) test?

The grade of this sixth and (final) test would be 91.

Step-by-step explanation:

This is an arithmetic series since each time the data is increasing by the common difference of 4, and we already know a₁ which is the first term in the sequence is 71, therefore we can say:

a₁ = 71

r = 4

a₆ = the sixth term that needs to be found out

n = 6

Formula of an arithemetic series:

aₙ = a₁ + r(n - 1)

a₆ = 71 + 4(6 - 1)

a₆ = 71 + 4(5)

a₆ = 71 + 20

a₆ = 91

Hence, the grade of this sixth and (final) test would be 91.

Hope this helps!

im pretty sure its

(8,15)

step-by-step explanation:

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.