Which statement make correctly uses limits determine a vertical asymptote of G(x)=-7(x-5)^2(x+6)/(x-5)(x+5)

There is a vertical Asymptote at x = 5 because

There is a vertical Asymptote at x = -5 because

Step-by-step explanation:

The exact question is as follows :

Given - G(x) = -7(x-5)^2(x+6)/(x-5)(x+5)

To find - Which statement make correctly uses limits determine a vertical Asymptote of G(x)

Solution -

Vertical Asymptotes are vertical lines which correspond to the zeroes of the denominator of a rational function.

Here the given function is the rational function

Denominator of G(x) = (x - 5)(x + 5)

So,

Put denominator = 0, we get

(x - 5)(x + 5) = 0

⇒x = 5, -5

∴ we get

G(x) has vertical Asymptotes at x = 5 and x = -5

Now,

At  x= 5

And

At x = -5

∴ we get

There is a vertical Asymptote at x = 5 because

There is a vertical Asymptote at x = -5 because

step-by-step explanation: 4 cause 2+2=4