What is the probability that a randomly selected value from the distribution will be less than 2.1 standard deviation from the mean

0.9821

Step-by-step explanation:

Probability that a randomly selected value will be less than 2.1 deviations from the mean ; this means the Zscore = 2.1

Hence, using :

P(Z < 2.1) = 0.9821 (standard normal table

= 0.9821

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05

answer: i literally just answered this question but they want me to do it again

step-by-step explanation: