Pls help will mark brainliest

Step-by-step explanation:

We are given the square root function below:

Recall that domain is the set of all x-values and that a number inside the square root cannot be negative.

From the given square root function above, substituting x >= 2 gives a positive output. But if we substitute x < 2, evaluating the numbers inside result in negative number in the square root which does not exist in Real Number.

Hence,

And thus, the domain is

Since if x < a, the output would become an imaginary number.

From the given function,

From the form of sqrt(x-a) where domain is a-term which is 2.

Since a = 2, and thus

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6