09.03 MC) What is the domain of the following parabola? (5 points) u-shaped graph that opens down with a vertex of 2, 3 Select one: a. x ≥ 2 b. x ≤ −1 c. y ≤ 3 d. All real numbers

The correct option is d: All real numbers.

Step-by-step explanation:

For a function f(x), the domain is the set of all the possible values of x that we can input in that function.

A general way to find the domain of a function is:

First, assume that the domain is the set of all real numbers.

Then, look at restrictions implied:

like in functions like:

f(x) = 4   if x > 3

Here the domain of the function is implied.

Third, let's find values of x that make "problems" with our function (for example, a zero in the denominator) and then remove these points from the domain.

In this case, we have a quadratic function:

y = a*x^2 + b*x + c

Here we do not have any problem (like a zero in a denominator), and we do not have any restrictions (We only know that the parabola is U shaped, so it is a function, and that its vertex is (2, 3) )

Then we can conclude that the domain of this function is the set of all real numbers.

The correct option is d: All real numbers.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: