2(x + 10) = -60 solve for x

2x + 20 = -60

-20           -20

2x = -80

Divide by 2 on both sides.

X = -40

-40

Step-by-step explanation:

2(x + 10) = -60

step 1 distribute the 2 to the x and 10

2 * x = 2x

2 * 10 = 20

we now have 20 + 2x = -60

step 2 subtract 20 from each side

20 - 20 cancels out

-60 - 20 = -80

we now have 2x = -80

step 3 divide each side by 2

2x / 2 = x

-80 / 2 = -40

we're left with x = -40

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.