Dev has 9 shells. Zoe has 55 shells. Zoe gives some shells to Dev. Now Zoe has 3 times as many as Dev. How many shells does Zoe give to Dev?

let the initial number of shells that dev has be A, and initial number of shells that zoe has be B. let the number of shells that zoe gives to dev be x. after giiving x shells zoe is left with 3 times the number of shell as that of dev. therefore number of shells with zoe = 3×number of shells with dev.

Step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3