Find a solution for each variable based on the given information. If (11+x) is positive, but (4+x) is negative, what is one number x could be?
If (−3+y) is positive, but (−9+y) is negative, what is one number that y could be?
If (−5+z) is positive, but (−6+z) is negative, what is one number that z could be?

Problem 1)

Sample value is -6.

Problem 2:

Sample value is 6.

Problem 3:

Sample value is 5.5.

Step-by-step explanation:

We can write inequalities to represent each situation.

Problem 1)

(11 + x) is positive and (4 + x) is negative. In other words:

Solving for x yields:

Combining them:

Any values that satisfy this inequality will work.

An example will be -6.

Problem 2)

(-3 + y) is positive and (-9 + y) is negative. Hence:

Solving for y yields:

So:

A sample value will be 6.

Problem 3)

(-5 + z) is positive and (-6 + z) is negative. Hence:

Solving for z yields:

So:

A sample value will be 5.5.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

irrational, cannot