10. Complete.

y^2 + 15y + 56 = (y + 7)(y + )

A. 8

B. –7

C. –8

D. 7

I would go with letter B. -7

Step-by-step explanation:

The two factors of a quadratic equation can be multiplied to form the original equation. Let the missing term be a:

y² + 15y + 56 = (y + 7)(y + a)

y² + 15y + 56 = y² + (7 + a)y + 7a

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Step by Step Solution

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Step by step solution :

STEP  1 :

Trying to factor by splitting the middle term

1.1     Factoring  y2+14y+49  

The first term is,  y2  its coefficient is  1 .

The middle term is,  +14y  its coefficient is  14 .

The last term, "the constant", is  +49  

Step-1 : Multiply the coefficient of the first term by the constant   1 • 49 = 49  

Step-2 : Find two factors of  49  whose sum equals the coefficient of the middle term, which is   14 .

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  7  and  7  

                    y2 + 7y + 7y + 49

Step-4 : Add up the first 2 terms, pulling out like factors :

                   y • (y+7)

             Add up the last 2 terms, pulling out common factors :

                   7 • (y+7)

Step-5 : Add up the four terms of step 4 :

                   (y+7)  •  (y+7)

The solution is:

  y  =  -7  

 The solution is:

 y = -14 / 2 = -7

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

c.   x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

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to solve the proportion, we'll cross multiply by multiplying numerator with denominator across the equal sign.