Use the quadratic formula to solve -125x^2+30000x-153000

(-b±√(b²-4ac))/(2a)

x=120±6434−−−√

x=−4.996

x=244.996

Find the Solution for

−125x2+30000x+153000=0

using the Quadratic Formula where

a = -125, b = 30000, and c = 153000

x=−b±b2−4ac−−−−−−−√2a

x=−30000±300002−4(−125)(153000)−−−−−−−−−−−−−−−−−−−−−√2(−125)

x=−30000±900000000−−76500000−−−−−−−−−−−−−−−−−−−√−250

x=−30000±976500000−−−−−−−−√−250

The discriminant b2−4ac>0

so, there are two real roots.

Simplify the Radical:

x=−30000±1500434−−−√−250

x=−30000−250±1500434−−−√−250

Simplify fractions and/or signs:

x=120±6434−−−√

which becomes

x=−4.996

x=244.996

yo answer should be 6 if im not mistaken

step-by-step explanation: