The curve with the equation y=ax^3-4x+1 is parallel to the line y=50x-1 at the point with x coordinate 3. (a) find the gradient of the curve at the point with x coordinate 4

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

it’s supposed to be -4+45=41

step-by-step explanation: