1 point 1. The table below shows information about the total weekly costs to display advertisements on a website and in a newspaper. Weeldy Advertising Coute Website Newspaper Total Cost (%) Advertisements Advertisements 1 1 195. 1 + 220.1 2 135 • 3 • 2202 5 135.5 • 220 - 3 7 135 -7 220 4 Based on the normation born in the table, which expension can be wa w determine the weekly an, in ders, of m werk drewspaper aniston] A 355mp B. 355 + m +P C. 135m + 220p D. 220m + 135P​

addition

step-by-step explanation:

for future students the answer is b

hope i

-lavira: )

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.