Let f(x)=√3x and g(x)=x-6 What's the smallest number that is in the domain of fog?

9514 1404 393

  6

Step-by-step explanation:

Maybe you have ...

  f(x) = √(3x)

  g(x) = x-6

Then ...

  f(g(x)) = √(3(x -6))

The square root function is only defined for non-negative arguments, so we require ...

  3(x -6) ≥ 0

  x -6 ≥ 0 . . . . . divide by 3

  x ≥ 6 . . . . . . . . add 6

The smallest number in the domain of f(g(x)) is x = 6.

dwe

step-by-step explanation:

ewd

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!