Jordan’s Cat Fern is a finicky eater. Jordan is trying to determine which of two brands of canned cat food Fern prefers.

There is significant difference in difference in the amount of food ferns eat ; and the preferred is TAB-a-cat.

(0.216, 5.984)

Step-by-step explanation:

This is a 2 sample t test test problem :

The hypothesis :

H0 : μ1 = μ2

H1 : μ1 ≠ μ2

x1 = 85.2 ; x2 = 82.1 ; n1 = 31 ; n2 = 30 ; s1 = 3.45 ; s2 = 4.62

The test statistic :

T = (x1 - x2) / √(s1²/n1 + s2²/n2)

T = (85.2 - 82.1) / √(3.45²/31 + 4.62²/30)

T = 3.1 / 1.0466

T = 2.96

Using the Pvalue from Tstatistic calculator :

df = smaller n - 1 = 30 - 1 = 29

Pvalue(2.96, 29) = 0.006075

α = 0.05

Pvalue < α ; We reject the Null and conclude that there is significant difference in difference in the amount of food ferns eat.

99% Confidence interval :

The test statistic :

(x1 - x2) ± Tcritical *√(s1²/n1 + s2²/n2)

Tcritical at 99% = Tcritical(0.01, 29) = 2.756

(85.2 - 82.1) / 2.756*√(3.45²/31 + 4.62²/30)

3.1 ± 2.8844296

Lower boundary = (3.1 - 2.8844296) = 0.216

Upper boundary = (3.1 + 2.8844296) = 5.984

(0.216, 5.984)

Since interval does not contain 0, then, we reject the Null.

the answer would be the last one (constat) she stays at the same rat every two mintues it goes up by 0.4

step-by-step explanation:

rounding to the nearest thousandth would be 452,000