Angles: Arcs & Angles need help thank you!!

See answers below

Step-by-step explanation:

1) The typr of triangle in a semicircle is a right angle. Hence the measure of  m<ABC  is 90degrees

2) m<DEF = 1/2(144)

m<DEF = 144/2

m<DEF = 72degrees

3) From the trinagle

4x+3 + x+7 +90 ==180

5x + 100 = 180

5x = 180-100

5x = 80

x = 80/5

x = 16

<QRD =  x+7

m<QRD = 16 + 7

m<QRD = 23degrees

4)  Angle in the same segment are equal

5x-37= 3x+1

5x - 3x = 1+37

2x = 38

x = 38/2

x =19

arc NM = 2m<P

arc NM = 2(3x+1)

arc NM = 2(3(19)+1)

arc NM = 2(58)

arcNM = 116degrees

it should be a and d. lmk if i'm wrong xd

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option