A train travels a distance of 120 km at a constant speed of V kmh 1. If the speed is reduced by 10kmh), then the time taken to the journey is increased by one
hour. Find the constant speed V of train.

Help me please

V = 40 km/h

Step-by-step explanation:

Total distance = 120 km

Constant speed of train = V km/h

⇒

Its given that if speed is reduced by 10 km/h , the time taken by train increases by 1 hour. BUT THE DISTANCE REMAINS SAME. So,

Factorise the quadratic equation.

Speed can't be negative. So , V = 40 km/h

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so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

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