Solve the problem. An experiment consists of randomly choosing a number between 1 and 10. Let E be the event that the number chosen is even. Assuming that each of the numbers between 1 and 10 is equally likely to be chosen, find P(E). A) .5
B) .8
C) .1
D) .2

A.

Step-by-step explanation:

1. the required probablilty is: P=(number_of_even_numbers)/(number_of_all_the_numbers);

2. according the condition the number of all the numbers is 10; the number of even numbers is 5 (they are: 2; 4; 6; 8; 10), then

3. P=5/10=0.5 (option 'A').

if you was gonna solve for a, a is a   < -12