Consider a random variable Z which has a standard normal distribution (mu = 0, sigma = 1). Choose which of the following values would be equivalent to the following probability: P (Z > 0.54)
A. P(Z > 0.54.
B. P(Z < 0.54).
C. 1 - P(Z < - 0.54).
D. 1 - P(Z < 0.54).

A. P ( Z > 0.54)  = 0,7054

B. P ( Z < 0.54)  =  0.2946

C.1) 1  -  0.2946    =  0.7054

D.1)  1  -  0.2946    =  0.7054

Step-by-step explanation:

A) P ( Z > 0.54)  =  1  -  P (  Z  ≤ 0.54)

P (  Z  ≤ 0.54)  =  0,2946          from  z-table

P ( Z > 0.54)  =  1  - 0,2946

P ( Z > 0.54)  = 0,7054

B) P ( Z < 0.54)  =  0.2946

C)  1 - P ( Z < - 0,54)

     1  -  0.2946    =  0.7054

D)  1 - P ( Z <  0,54)

     1  -  0.2946    =  0.7054

for the points! : )

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°