A fertilizer moxture is prepared by miscing urea and super phosphate in the ratio
3:5. the ratio between the proces of
Ured and phosphate is 1:2. If the
price of 1 kg of the mixture is Rs.
13,000 find the cost of 1kg of super
phosphate

The answer is c because you turn 17.5% into a decimal which gives you .175 then you times that by $361.35 which gives you 63.23625 but then you round that which gives you 63.24. then you at 63.24 pulse 361.35 and you round it which gives you $425

Ya i could just need to know what type of math