Solve the trigonometric equation on the interval of [0,2π) below:
Show your work, thanks! ​

Step-by-step explanation:

we would like to solve the following trigonometric equation on interval of [0,2π)

remember that,

so the equation has two solutions

take inverse trig both sides which yields:

simplify the second equation:

add period of 2kπ:

By making theta subject of the equation we acquire:

since we get:

as we want to Solve the trigonometric equation on the interval of [0,2π) we get

by simplifying we acquire:

and we are done!

hence,

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step-by-step explanation: