Points A, B, C, and D are the vertices of a square. Points E and F are the center of two congruent semicircles that are tangent to each other at point G. Which value is closest to the area of the shaded regions? ​

8 sq units

Step-by-step explanation:

to find the area of shaded region:

area of square minus sum of areas of each semi-circle

A(square) = 6² = 36

A (semi-circle) = πr²/2

= π3²/2

= 4.5π

Since there are two semi-circles, that makes one complete circle with an area of 9π

A(circle) ≈ 28 sq units

36-28 = 8 sq units

8 square units

Step-by-step explanation:

good luck

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

24

step-by-step explanation: