Janice rides the bus to school each day. She always arrives at her bus stop on time, but her bus is late 80% of
the time
Janice runs a simulation to model this using a random
number generator. She assigns these digits to the possible
outcomes:
. Let 0 and 1 = bus is on time
• Let 2, 3, 4, 5, 6, 7, 8, and 9 = bus is late
The table shows the results of the simulation.
Group number 1 2 3 4
Random digita 42544 90425 81226 48768 17297
5
Group number 6 7 8 9 10
Random digita 5021394383 B7964 83458 11486
What is the estimated probability that Janice's bus will be late every day next
week?
OA-50%
OB = 60%
ci = 0%
ODB = 30%

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.

i believe a. 12x≥120 is the answer