Suppose that the number of gallons of milk sold per day at a local supermarket are normally distributed with mean and standard deviation of 486.9 and 24.01, respectively. What is the probability that on a given day the supermarket will sell between 477 and 525 gallons of milk

0.6032 = 60.32% probability that on a given day the supermarket will sell between 477 and 525 gallons of milk

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean and standard deviation of 486.9 and 24.01, respectively.

This means that

What is the probability that on a given day the supermarket will sell between 477 and 525 gallons of milk?

This is the p-value of Z when X = 525 subtracted by the p-value of Z when X = 477.

X = 525

has a p-value of 0.9441

X = 477

has a p-value of 0.3409

0.9441 - 0.3409 = 0.6032

0.6032 = 60.32% probability that on a given day the supermarket will sell between 477 and 525 gallons of milk

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

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step-by-step explanation: