Sec0 = -13/12 and cot0 < 0, find exact values of tan0 and sin0.

Solution given;

Sec θ=-

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

cosθ=

=

b=12

h=13

By using Pythagoras law

p=

Now

exact values of tan θ==

since it lies in II quadrant

tan θ=-

and

sinθ==

since it lies in II quadrant

sin θ=

-14 is the answer

hope this : ))

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.