Mathematics, 29.05.2021 05:40 meganwintergirl
Triangle XYZ is reflected across the x-axis to produce triangle X'Y'Z'. Then triangle X'Y'Z' is rotated 90° counterclockwise about the origin to create triangle X"Y"Z". If triangle X"Y"Z" has vertices X"(4, 0), Y"(2, −1), Z"(2, 1) what are the coordinates of the vertices of triangle XYZ?
Answers: 3
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Graph g(x)=2cosx . use 3.14 for π . use the sine tool to graph the function. graph the function by plotting two points. the first point must be on the midline and closest to the origin. the second point must be a maximum or minimum value on the graph closest to the first point.
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Aline that intersects one of two parallel lines intersects the other also always sometimes never
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In δabc shown below, ∠bac is congruent to ∠bca: triangle abc, where angles a and c are congruent given: base ∠bac and ∠acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: m∠bda and m∠bdc is 90° by the definition of a perpendicular bisector. ∠bda is congruent to ∠bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)
Answers: 1
Triangle XYZ is reflected across the x-axis to produce triangle X'Y'Z'. Then triangle X'Y'Z' is rota...
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