Outside the court ard is 120 m“, find the width of the path. A square garden has an area of 441 m². If the path of uniform width surrounding inside the
garden is 216 m², find the width of the path.
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Area of a square garden = 2, 500 m².

Length of the side of the garden =  √2,500 = 50 m.

Width of the path = 2.5 m.

Path is inside the garden.

Width of the garden that is inside (enclosed) by the path:

        50 - 2 * 2.5 = 45 m.

Length of the garden inside by the path :  = 45 m.

So the area of garden inside the path = 45 * 45 m²

     = 2, 025 m².

Area of the path = 2, 500 - 2, 025  

    = 475 m².

Cost of laying the path = Rs 25 /m² * 475 m²

   = Rs 11, 875.

Step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )