There exist two complex numbers $c$, say $c_1$ and $c_2$, so that $3 + 2i$, $6 + i$, and $c$ form the vertices of an equilateral triangle. Find the product $c_1 c_2$ in rectangular form.

The answer is ""

Step-by-step explanation:

Distance

midpoint height

let

Gradient      

Perpendicular Gradient

midpoints

Similar to perpendicular

Now I'll obtain the perpendicular bisector solution

An equation of the center circle radius will be.

step-by-step explanation:

we are given

since, we have to isolate x on anyone side

so, we can move all x terms on one side

subtract both sides by 2x

add both sides by 9

divide both sides by 4

we get

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