Problem #4: and one
sum of
A gumball machine contains 15 green gumballs, 6 yellow gumballs, and
11 pink gumballs.
The gumball machine dispenses 1 gumball at a time.
a) What is the probability of getting a pink gumball?
b) What is the probability of getting three pink gumballs in a
row?
c) If the machine was refilled, and you purchased 4
gumballs, what is the theoretical probability of the machine
dispensing 4 green gumballs?
d) If we add 8 orange gumballs to the machine, what is the probability
of getting two orange gumballs and then a yellow gumball.
be closest
at 18.

Step-by-step explanation:

Prepare closing entireties for the concert hall bond fund

you are uyytr tyy

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt