Professor Rosencrantz flips a fair coin once. Professor Guildenstern flips a fair coin three times. What is the probability that Professor Rosencrantz obtains more heads than Professor Guildenstern

9/13 = 0.6923

Step-by-step explanation:

We start by defining

A as event that head was flipped

B1 = event that coin is biased

B2 = event that it is unbiased

P(B1) = 3/5

P(B2) = 2/5

P(A|B1) = 3/4

P(A|B2) = 2/4 = 1/2

When we solve this using bayes theorem we have to find

p(B1|A) = [P(B1) x P(A|B1)]/[P(B1) x P(A|B1) + P(B2) x P(A|B2)

= 0.6 x 0.75 / 0.6 x 0.75 + 0.4x0.5

= 0.45/0.45+0.2

= 0.45/0.65

= 0.6923

please brainliest

answer: a.   one is a factor of every whole number since every number is divisible by itself.