Find a polynomial f(x) of degree 3 that has the following zeros. -5, 8, 2 Leave your answer in factored form

f(x) = (x+5)(x-8)(x-2)

Step-by-step explanation:

If we know the zeros, the polynomial is of the form

f(x) = (x-a)(x-b)(x-c)  where a,b,c are the zeros

f(x) = (x - -5)(x-8)(x-2)

f(x) = (x+5)(x-8)(x-2)

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