A DrillingRick was diggingA well in the valley it dug to a point of -50 Meters in one day After 18 hours at how many meters would the rig be if it moved at the same amount each hour? Show your work. Explain your answer

37.5 meters

Step-by-step explanation:

depth of well : hours of digging

it dug to a point of -50 Meters in one day

= 50 meters : 24 hours

After 18 hours at how many meters would the rig

Let

x = depth that will be rigged

depth of well : hours of digging

= x meters : 18 hours

Equate the ratios

50 meters : 24 hours = x meters : 18 hours

50/24 = x/18

50 * 18 = 24 * x

900 = 24x

x = 900/24

x = 37.5

x = depth that will be rigged = 37.5 meters

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3