Which equations have no real solution but have two complex solutions? A 3x>2-5=-8 b 2x>2=6x-5 c 12x=9x>2 +4 d -x>2 - 10x =34

Step-by-step explanation:

The equations are:

(a)

Add 8 to both sides

To do this, we simply calculate the discriminant (d) using:

If

Then it has complex roots

Where:

--- complex root

(b)

Equate to 0

--- complex root

(c)

Equate to 0

---- real roots

(d)

Equate to 0

---- complex root

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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