In a 3-digit number, the humdrends digit is one more than the ones digit and the tens digit is twice the hunderends digit. If the sum of the digits. Is. 11, find the number

362

Step-by-step explanation:

let the digits that make up the number be a, b and c with a in the hundred position, b in the tens and c in the units position. Given that

he hundreds digit is one more than the ones digit

a = c + 1

c = a - 1

and the tens digit is twice the hundreds digit

b = 2a

If the sum of the digits is 11

a + b + c = 11

substituting

a + 2a + a - 1 = 11

4a - 1 = 11

4a = 11 + 1

4a = 12

a = 12/4

= 3

recall that

c = a - 1 = 3 - 1 = 2

b = 2a = 2 * 3 = 6

Hence the number is 362

easy its decreasing

step-by-step explanation:

because its top point is at the to of the graph on the left side (atleast from the veiw i see it) now if that top point wast in the lower part of the graph it would be increasing hope this have a nice day