Sandy mixed together 9 gallons of one brand of juice and 8 gallons of a second brand of juice, which contains 48 percent real fruit juice. Find the percent of real fruit juice in the first brand if the mixture contained 30 percent real fruit juice. Which of the following equations could be used to solve this? Group of answer choices

a(9)+48(8)17=0.30100

a(9)+0.48(8)17=30100

a(9)+0.48(8)a+0.48=30100

a(9)+0.48(8)17=30

14 %   pure juice comes from  first brand

Step-by-step explanation:

Mixture:

17 gal 30% contains:  17x 30% = 5.10 gal pure juice

 Second brand:

8 gal 48% contains:  8x40% =  3.84   gal pure juice

5.10 − 3.84 = 1.26   gal

1.26   gal is  coming  from 9 gal of first  brand

The percentage of first brand  is:

(1.26/9) x100  =  14 %   pure juice.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph