A student solves the equation for v. Start with the original equation. k = one-half m v squared
Use the square root property. StartRoot k EndRoot = one-half m StartRoot v squared EndRoot
Use the division property of equality. StartRoot k EndRoot divided by m = (one-half m v) divided by m
Use the multiplication property of equality. 2 times StartFraction StartRoot k EndRoot Over m EndFraction = one-half v times 2
Simplify. StartFraction 2 StartRoot k EndRoot Over m EndFraction = v

Which statement explains how to correct the error that was made?
The subtraction property of equality should have been applied to move m to the other side of the equation.
The multiplication property of equality should have been applied before the division property of equality.
The division property of equality should have been applied to move the fraction to the other side of the equation.
The square root property should have been applied to both complete sides of the equation instead of to select variables.

4 + 5 7/9= 9 7/9

step-by-step explanation:

answer: sorry i dont really know but can we talk all my friends r gone and im bored

step-by-step explanation:

a) 40 more; b) old factory:   10%, new factory:   16%; c) week 4

explanation:

a) at week 0, we see in the graph that the new factory produces 190 specialty items.  

using the function, substituting 0 in for w,

this is a difference of 230-190 = 40.

b) the function for the old factory is written in the form f(x) = a(1+r)ˣ, where a is the original amount, x is the amount of time and r is the growth rate.   the equation for the old factory is ; 230 is in place of a and is the original amount; w is the amount of time; which means 1+r = 1.1.   this means that r must be 0.1 or 10%.

for the new factory, we find the percent of increase to find the growth rate; the formula for this is

between the first two points, the amount of change is 220-190 = 30; this gives us

30/190 = 0.158 ≈ 0.16 = 16%

c) at week 0, the old factory has 230 while the new factory has 190.

at week 1, the old factory has 230(1.1) = 253 while the new factory has 220.

at week 2, the old factory has 230(1.1²) = 278.3 while the new factory has 252.

at week 3, the old factory has 230(1.1³) = 306.13 while the new factory has 290.

at week 4, the old factory has 230(1.1⁴) = 336.743 while the new factory has 337.   this is the first week that the new factory surpasses the old.