During battling practice, two pop flies are hit from the same location, 2s apart the paths are modeled by the equations h equal negative 16t squared + 56t and h = -16t + 156t - 248 where t is the time that has passed since the first ball was hit

Step-by-step explanation:

To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.

h = -16t^2 + 56t

h = -16t^2 + 156t - 248

-16t^2 + 56t = -16t^2 + 156t - 248

You can cancel out the -16t^2's to get

56t = 156t - 248

=> 0 = 100t - 248

=> 248 = 100t

=> 2.48 = t

Using this time value, plug into either equation to find the height.

h = 16(2.48)^2 + 56(2.48)

Final

h = 40.4736

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,